While I was compiling the index to this blog, I noticed that I had written several posts about mechanical simple harmonic oscillators but hadn’t written anything about electrical simple harmonic oscillators– the subject of this post.

A simple harmonic oscillator is a system that oscillates indefinitely by exchanging potential and kinetic energy. In a real system there will be some dissipation of energy and so cannot oscillate for ever – the simple harmonic oscillator is a model for a real system and not an exact description of it. Examples are a pendulum and a vertical oscillating spring. Both systems will dissipate some energy because, for example, of the viscosity of the air. But the simple harmonic oscillator describes the behaviour of both reasonably well. For example, a mass bouncing on the end of a spring, oscillates with a frequency of

*f* = (1/2π)(*k/m*)^{1/2} (1)

where *k* represents to stiffness of the spring and *m* is the mass of the object hanging from its end.

In the picture above, the vertical spring supports a mass; the force, exerted by the gravitational field of the earth, on this mass stretches the lower end of the spring from P’ to O. Now an additional force is applied to stretch it to P. This additional stretching of the spring gives it potential energy. When this additional force is removed, the potential energy is converted into kinetic energy. This kinetic energy tends to return the spring to its equilibrium position. But it does not stop at O because all its potential energy is converted into kinetic energy – so it continues to move upwards, converting kinetic energy into gravitational potential energy as it continues. When all the kinetic energy has been converted into potential energy, the direction of movement changes as the mass begins to fall. If the system did not dissipate energy, it would oscillate indefinitely. Whenever the kinetic energy is zero, the energy of the system will be stored as potential energy that will be used to restore motione. For example, the spring, in the picture below, oscillates between P and P’; at O the kinetic energy is maximum but the system has no potential energy, as described in post 18.11.

From the analogy between electrical and mechanical systems, we can see that a capacitor behaves like the spring (because it stores energy) and an inductor behaves like the mass (because it is the inertial component of the system opposing change). Then an electrical simple harmonic oscillator will consist of the circuit shown above, in which a capacitor discharges through an inductor.

Initially, the charged capacitor has potential energy. As it discharges, charges begin to move around the circuit – the moving charges have kinetic energy. But the inductor opposes the movement of charge in the circuit. In the mechanical system, a stretched spring has potential energy. When the spring is released, this potential energy is converted into kinetic energy. But the mass hanging on the end of the spring opposes the change in motion, so that the system oscillates. The charge in the electrical circuit oscillates in exactly the same way. Returning to our analogy between electrical and mechanical systems (and applying it to equation 1), the charge (and, therefore, the current) oscillates with a frequency of

*f* = (1/2π)(*1**/LC*)^{1/2} (2)

where *L* is the inductance (analogous to inertia) of the inductor and *C* is the capacitance (analogous to inverse stiffness or compliance) of the capacitor. A real electrical system will have some resistance, dissipating energy, so the simple harmonic oscillator is a model for a capacitor discharging through an inductor in a circuit with negligible resistance.

We can also analyse the behaviour of the electrical circuit directly, without needing to think about the analogy with a mechanical system. In the appendices, I have done this in three different ways.

This blog now has an INDEX.

Related posts

19.17 Computer modelling – the simple harmonic oscillator

18.24 Analogies between electrical and mechanical systems

18.23 Frequency response and resonance in electrical systems

18.22 Inductors and impedance

18.21 Inductors and inductance

18.20 Capacitors and impedance

18.19 Capacitors and capacitance

18.17 Euler’s relation, oscillations and waves

18.8 Natural frequency and resonance

18.11 Motion in a circle, the simple harmonic oscillator and waves

18.7 The simple pendulum

18.6 The simple pendulum: a simple harmonic oscillator

Appendix 1: Analysing the electrical simple harmonic oscillator using the concept of impedance

The modulus of the complex number that represents the impedance of an electrical circuit containing a resistor, an inductor and a capacitor is given by

where *R* is the resistance of the circuit and *ω* is the angular frequency of the oscillating current. When we can consider that *R* = 0, the impedance becomes

In our electrical simple harmonic oscillator, charge flows from the discharging capacitor; there is no other potential difference causing charge to flow. So, the current is maximised when │*Z*│ = 0, that is when

The relationship between angular frequency and frequency is that *ω*= 2π*f*, so that this result is equivalent to equation 2.

Appendix 2: Analysing the electrical simple harmonic oscillator using the concept of electrical potential

The capacitance of a capacitor is defined by

*C* = *Q*/*V’*

where *Q* is the stored charge and *V’* is the potential difference across the capacitor. When the capacitor discharges, it creates an equal and opposite potential difference in the circuit it discharges into. This potential difference is

*V* = –*V*’ = – *Q/C*.

The inductance, *L*, of an inductor is defined by the equation

*V* = *L*(d^{2}*Q*/d*t*^{2})

when *V* is the potential difference causing charges to move through the inductor. The term (d^{2}*Q*/d*t*^{2}) represents double differentiation with respect to time. If this potential difference is created by a discharging capacitor

*L*d^{2}*Q*/d*t*^{2} = – *Q/C*. or d^{2}*Q*/d*t*^{2} = – *Q*/(*LC*). (B1)

To solve this differential equation, we will consider a trial solution of the form

*Q* = *Q*_{0}*e ^{i}*

*(B2)*

^{ωt}where *Q*_{0} is the value of *Q* when *t* = 0, *e* has a value of approximately 2.718, *i* is the square root of -1 and *ω* is an angular frequency. Differentiating this trial solution with respect to *t* gives

d*Q*/d*t* = *i**ωQ*_{0}*e ^{i}*

^{ωt}d^{2}*Q*/d*t*^{2} = *–**ω*^{2}*Q*_{0}*e ^{i}*

*= –*

^{ωt}*ω*

^{2}

*Q*(B3)

Comparing equations B1 and B3, the trial solution works when

*ω*= 1/(*LC*)^{1/2}.

Noting the relationship between frequency and angular frequency (appendix 1), this result is equivalent to equation2.

Differentiating equation B2 gives the current in the circuit

*I *= d*Q*/d*t* = *i**ωQ*_{0}*e ^{i}*

*=*

^{ωt}*i*

*ωQ*

_{0}cos(

*ωt*) –

*ωQ*

_{0}sin(

*ωt*).

The final step comes from Euler’s relation. The result is a complex number. Since the current in the circuit must be real, it is represented by the real part

*I* = – *ωQ*_{0}sin(*ωt*) = – *I*_{0}sin(*ωt*)

where *I*_{0} is the peak value of the current; the minus sign simply represents the (arbitrary) direction in which the oscillating current is flowing.

Appendix 3: Analysing the electrical simple harmonic oscillator using the concept of energy

From the analogy between electrical and mechanical systems, the charged capacitor has an energy of *Q*^{2}/2*C* and the energy of the current flowing in an inductor is *LI*^{2}/2 = (*L*/2) (d*Q*/d*t*)^{2}; the final step comes from the definition of current, where *t* represents time.

Since all the charge in the circuit came originally from the charged capacitor,

(*L*/2)(d*Q*/d*t*)^{2}– *Q*^{2}/2*C* = 0 or *L*(d*Q*/d*t*)^{2} = *Q*^{2}/*C*.

Differentiating this result with respect to *t* gives

2*L*(d*Q*/d*t*)(d^{2}*Q*/d*t*^{2}) = (2*Q*/*C*)(d*Q*/d*t*)

as described in post 18.6. Dividing both sides of this equation by 2(d*Q*/d*t*) gives

d^{2}*Q*/d*t*^{2} = – *Q*/(*LC*).

This result is identical to equation B1 and so has the same solution.