*Before you read this, I suggest you read* posts 16.44 and 17.6.

Suppose you are asked to find out whether a gold ring is made of solid gold or a cheaper metal with a gold coating. You need to do this without damaging the ring. How are you going to do it?

The simplest way is to measure its density. Cheaper metals have a lower density than gold (post 16.44). So, a cheap ring with a gold coating will have a lower average density than a ring of solid gold.

One way of measuring the density is to use Archimedes principle (post 17.6). You need to weigh the ring surrounded by air and then surrounded by water, as shown in the pictures above. When you weigh something, the device that you use will measure the gravitational force but will tell you the mass of the object (post 16.17). To weigh the ring in water you will need to suspend it with a thread (post 17.6); so you will need to weigh the thread to make sure that its mass is negligible compared to the mass of the ring.

Suppose the mass of the ring is 5.3 g (remember that g is the abbreviation for a gramme, post 16.13) and appears to be 5.0 g when surrounded by water. We expect the apparent mass to be less when the ring is surrounded by water because its weight is less – its weight is less because the water gives some support to the water (see post 17.6). This support is sometimes called *buoyancy*.

According to Archimedes principle, if the ring has a volume *V* and an average density *ρ* its weight in air will be

*W _{air}* =

*V*

*ρg*

and its weight in water will be

*W _{water}* =

*Vg*(

*ρ*–

*ρ*).

_{o}This is explained in post 17.6. Here *ρ _{o}* is the density of water and

*g*is the modulus of the gravitational field. It’s important to distinguish g, the standard abbreviation for a gramme, and

*g*(note the

*italics*) which is the symbol I’m using to represent the gravitational field (see post 16.13 to find out more).

If we divide the second equation by the first, we get the result that

*W _{water}*/

*W*= (

_{air}*ρ*–

*ρ*)/

_{o}*ρ*.

Some simple algebra (see appendix) gives the result that

*ρ* = [*W _{air}*/(

*W*–

_{air}*W*)]

_{water}*ρ*.

_{o}Since weight is proportional to mass (post 16.17) and the density of water is 1.0 ×10^{3} kg.m^{-3} (post 16.44) the average density of the ring is

[5.3/(5.3 – 5.0)] × 1.0 × 10^{3} = 18 × 10^{3} kg.m^{-3}.

This is less than the density of pure gold (see post 16.44).

However, solid gold jewellery is not pure gold; the gold is mixed with other metals to make it less soft (http://www.hsamuel.co.uk/webstore/jewellery/metalGuide/carats.cdo). The density of gold in jewellery varies from 18 × 10^{3} kg.m^{-3} (22 carat gold which is 91.6% pure gold) to 11 × 10^{3} kg.m^{-3} (9 carat gold which is 38% pure) (https://24carat.co.uk/densityofgoldandothermetalsframe.html).

So, the ring appears to be made of solid 22 carat gold.

In practice, you would need to investigate the precision of this result by repeating the measurements several times and calculating a standard deviation (post 16.24). The standard deviation could also be used to calculate the confidence interval in which you are 95% or 99% sure that the true value lies (post 16.26).

Finally, there are other ways of measuring the average density of the ring. Can you think of one?

*Related posts*

17.6 Floating

16.44 Density

16.7 Weight

__Appendix__

To derive *ρ* = [*W _{air}*/(

*W*–

_{air}*W*)]

_{water}*ρ*from

_{o}*W*/

_{water}*W*= (

_{air}*ρ*–

*ρ*)/

_{o}*ρ*.

Multiply both sides of the second equation by *ρW _{air}* to get the result

*ρW _{water}* = (

*ρ*–

*ρ*)

_{o}*W*.

_{air}Now subtract *ρW _{air}* from both sides of this equation to get

*ρW _{water}* –

*ρW*= –

_{air}*ρ*.

_{o}W_{air}Now multiply both sides of this equation by – 1 to give

*– ρW _{water}* +

*ρW*=

_{air}*ρ*.

_{o}W_{air}This result can be written as

*ρ*(*W _{water}* –

*W*) =

_{air}*ρ*.

_{o}W_{air}Dividing both sides of the equation by (*W _{water}* –

*W*) gives the required result.

_{air}